《学习OpenCV》第三章练习（参考代码）第7题-白红宇

《学习OpenCV》第三章练习（参考代码）第7题

阅读量：6830 次

发布时间：2019-06-26

本文共 1989 字，大约阅读时间需要 6 分钟。

#include
    
     #include
     
      #include
      
       int main(int argc, char** argv){	IplImage* img = cvLoadImage("E:\\1.jpg");	IplImage* red = cvCreateImage(cvGetSize(img), img->depth, 1);	IplImage* green = cvCreateImage(cvGetSize(img), img->depth, 1);	IplImage* blue = cvCreateImage(cvGetSize(img), img->depth, 1);	IplImage* green_image = cvCreateImage(cvGetSize(img), img->depth, img->nChannels);	cvSplit(img, red, green, blue, NULL);	cvZero(red);	cvZero(blue);	cvMerge(red, green, blue, NULL, green_image); 	cvNamedWindow("GreenChannel", CV_WINDOW_AUTOSIZE);	cvShowImage("GreenChannel", green_image);	//克隆这个绿图两次（分别命名为clone1和clone2）	//	IplImage* clone1 = cvCloneImage(green);	IplImage* clone2 = cvCloneImage(green);	//求出这个绿色平面的最大值和最小值	//	double min;	double max;	CvPoint minPtr;    CvPoint maxPtr;	cvMinMaxLoc(green, &min, &max, &minPtr, &maxPtr); //注意：输入的图象必须是单通道的	printf("Minimum: %lf, Position: (%d, %d) \n", min, minPtr.x, minPtr.y);	printf("Maximum: %lf, Position: (%d, %d) \n", max, maxPtr.x, maxPtr.y);	//将clone1的所有元素赋值为thresh = (unsigned char)((最大值-最小值)/2.0)	//	double thresh = (max-min)/2;	cvZero(clone1);	cvAddS(clone1, cvScalar(thresh), clone1);		//将clone2所有元素赋值为0，然后调用函数cvCmp(green_image, clone1, clone2, CV_CMP_GE)。	//现在clone2将是一个标识绿图中值超过thresh的掩码图象。	//	//如果green中的元素大于或等于clone1中对应位置的元素，那么clone2对应位置的像素值被设为255	cvCmp(green, clone1, clone2, CV_CMP_GE);	//最后，使用cvSubS(green_image, thresh/2, green_image, clone2)函数并显示结果	//	cvSubS(green, cvScalar(thresh/2), green, clone2);	IplImage* resultImg = cvCreateImage(cvGetSize(img), img->depth, img->nChannels);	cvMerge(red, green, blue, NULL, resultImg);	cvNamedWindow("FinalResult", CV_WINDOW_AUTOSIZE);	cvShowImage("FinalResult", resultImg);	cvWaitKey(0);	cvReleaseImage(&img);	cvReleaseImage(&red); 	cvReleaseImage(&green);	cvReleaseImage(&blue);	cvReleaseImage(&green_image);	cvReleaseImage(&clone1);	cvReleaseImage(&clone2);	cvDestroyWindow("GreenChannel");}